views:

119

answers:

3

Given the following LINQ to SQL query:

var test = from i in Imports
           where i.IsActive
           select i;

The interpreted SQL statement is:

SELECT [t0].[id] AS [Id] .... FROM [Imports] AS [t0] WHERE [t0].[isActive] = 1

Say I wanted to perform some action in the select that cannot be converted to SQL. Its my understanding that the conventional way to accomplish this is to do AsEnumerable() thus converting it to a workable object.

Given this updated code:

var test = from i in Imports.AsEnumerable()
           where i.IsActive
           select new 
           { 
               // Make some method call 
           };

And updated SQL:

SELECT [t0].[id] AS [Id] ... FROM [Imports] AS [t0] 

Notice the lack of a where clause in the executed SQL statement.

Does this mean the entire "Imports" table is cached into memory? Would this slow performance at all if the table contained a large amount of records?

Help me to understand what is actually happening behind the scenes here.

+11  A: 

The reason for AsEnumerable is to

AsEnumerable(TSource)(IEnumerable(TSource)) can be used to choose between query implementations when a sequence implements IEnumerable(T) but also has a different set of public query methods available

So when you were calling the Where method before, you were calling a different Where method from the IEnumerable.Where. That Where statement was for LINQ to convert to SQL, the new Where is the IEnumerable one that takes an IEnumerable, enumerates it and yields the matching items. Which explains why you see the different SQL being generated. The table will be taken in full from the database before the Where extension will be applied in your second version of the code. This could create a serious bottle neck, because the entire table has to be in memory, or worse the entire table would have to travel between servers. Allow SQL server to execute the Where and do what it does best.

Yuriy Faktorovich
So it still has deferred execution right? Using the above query as an example, the entire "Imports" table wont be stored in memory just the active ones, when I do something like "test.Dump()". Is that correct?
Mike Fielden
@Mike Fielden Well the entire table will go through memory as the Where is enumerating it. I'm not sure if all rows will be loaded into memory at the same time.
Yuriy Faktorovich
A: 

I believe the AsEnumerable just tells the compiler which extension methods to use (in this case the ones defined for IEnumerable instead of those for IQueryable). The execution of the query is still deferred until you call ToArray or enumerate on it.

Razvi
A: 

At the point where the enumeration is enumerated through, the database will then be queried, and the entire resultset retrieved.

A part-and-part solution can be the way. Consider

var res = (
    from result in SomeSource
    where DatabaseConvertableCriterion(result)
    && NonDatabaseConvertableCriterion(result)
    select new {result.A, result.B}
);

Let's say also that NonDatabaseConvertableCriterion requires field C from result. Because NonDatabaseConvertableCriterion does what its name suggests, this has to be performed as an enumeration. However, consider:

var partWay =
(
    from result in SomeSource
    where DatabaseConvertableCriterion(result)
    select new {result.A, result.B, result.C}
);
var res =
(
    from result in partWay.AsEnumerable()
    where NonDatabaseConvertableCriterion select new {result.A, result.B}
);

In this case, when res is enumerated, queried or otherwise used, as much work as possible will be passed to the database, which will return enough to continue the job. Assuming that it is indeed really impossible to rewrite so that all the work can be sent to the database, this may be a suitable compromise.

Jon Hanna
Jon, please indent your code with four spaces; or use the code button when creating your post, that way it's autoformatted. Also try to use backticks around classnames when using them in text, it's way more clear.
Jan Jongboom
Will do, it was my first answer, and I didn't notice the code element of the editor until my second.
Jon Hanna