How would I get just the filename without the extension and no path?
The following gives me no extension but I still have the path attached:
source_file_filename_no_ext=${source_file%.*}
views:
56answers:
2
+1
A:
Most UNIXes have a basename executable for just that purpose.
pax> a=/tmp/file.txt
pax> b=$(basename $a)
pax> echo $b
file.txt
If you want a bash-only solution, you can start with:
pax> a=/tmp/xx/file.tar.gz
pax> xpath=${a%/*}
pax> xbase=${a##*/}
pax> xfext=${xbase##*.}
pax> xpref=${xbase%.*}
pax> echo;echo path=${xpath};echo pref=${xpref};echo ext=${xfext}
path=/tmp/xx
pref=file.tar
ext=gz
That little snippet sets xpath (the file path), xpref (the file prefix) and xfext (the file extension).
paxdiablo
2010-07-29 13:29:04
I know there is something to do with bash like the above. I just don't know what the key word is. I would like to get get the pathname, filename, and extension separated into different variables.
Keith
2010-07-29 13:31:47
If you want to get path use:path=$(echo $filename | sed -e 's/\/[^\/]*$/\//')If you want to get extension:ext=$(echo $filename | sed -e 's/[^\.]*\.//')
jcubic
2010-07-29 13:38:26
@Keith: for pathname, use `path=$(dirname $filename)`; there isn't a command to give you the extension per se, but @paxdiablo showed you how the shell can do it.
Jonathan Leffler
2010-09-19 00:36:17
A:
$ source_file_filename_no_ext=${source_file%.*}
$ echo ${source_file_filename_no_ext##*/}
ghostdog74
2010-07-29 13:41:37