How to get following result in ASP.NET:
INPUT string: "Duck, Donald"
Required String: "Donald Duck"
P.S: The input string is dynamic.
views:
76answers:
4
+2
A:
Hey,
You have to write the code yourself to split by the , using the string's split method, and reverse them yourself.
Brian
2010-08-12 12:38:14
+1
A:
There's a million ways to skin a cat, but how about using Linq?
using System.Linq;
string input = "Duck, Donald";
string output = string.Concat(input.Split(',').Select(x => (" " + x)).Reverse()).Trim();
I'm sure someone will come up with an easier way!
nukefusion
2010-08-12 12:44:29
@nukefusion - thanks, i appreciate your help. But is the code for C# ? I have asp.net with VB and framework 1.1
RMN
2010-08-12 13:39:51
@RMN, are you using framework 1.1? Why oh why? Save yourself a lot of trouble and get a newer version
Esben Skov Pedersen
2010-08-12 13:47:58
i would definately love to do that, if that was in my hands :( Unfortunately i have no options other than solving this in 1.1 :)
RMN
2010-08-12 14:05:51
@RMN: Yeah, sorry, didn't see the VB tag.... doh!
nukefusion
2010-08-12 14:25:33
+5
A:
Dim name As String = "Duck, Donald"
If name.Contains(",") Then
Dim fullname As Array = Split(name.ToString, ",")
Dim final As String = fullname(1).trim() + " " + fullname(0).trim()
End If
Johnny DropTables
2010-08-12 13:42:09
highlight your example in the editor and click the little 101010 button to format it as code. also you should probably call `.Trim()` on each array item.
lincolnk
2010-08-12 13:50:17
@Johnny, Thanks. The suggestion looks good. Can you suggest me an additional 'if' condition to identify if there is any Comma in string, then only to reverse/split these strings. Probably can be exceptional condition.
RMN
2010-08-12 14:22:17
Dim name As String = "Duck, Donald" If name.Contains(",") Then Dim fullname As Array = Split(name.ToString, ",") Dim final As String = fullname(1).trim() + " " + fullname(0).trim() End If
Johnny DropTables
2010-08-12 14:31:27
+1
A:
You could create a function that takes the comma separated name as input, splits it and returns the new, rearranged name as output.
Public Function CreateName(ByVal name as String) as String
Dim values() as String = name.Split(",")
Dim newName as String = String.Empty
If values.length > 1 Then
newName = values(1).Trim() & " " & values(0).Trim()
Else
newName = values(0).Trim()
End If
Return newName
End Sub
.
.
.
Dim rearranged as String = CreateName("Duck, Donald")