ref and out in C++/CLI

Question

Hello

I know that the C++/CLI code

void foo(Bar^% x);

transforms into

Void foo(ref Bar x);

What is the C++/CLI code that becomes

Void foo(out Bar x);

?

Answer 1

There is no such specific syntax in C++/CLI. I think you can get fairly close by adding the OutAttribute to modify the parameter. But I'm not sure that achieves the exact same semantics as C# out.

The concept of out is for the most part limited to C#. The CLR really only sees ref parameters. The out concepts is achieved via a mod opt I believe and most languages ignore it.