views:

550

answers:

2

Suppose a shell script (/bin/sh or /bin/bash) contained several commands. How can I cleanly make the script terminate if any of the commands has a failing exit status? Obviously, one can use if blocks and/or callbacks, but is there a cleaner, more concise way? Using && is not really an option either, because the commands can be long, or the script could have non-trivial things like loops and conditionals.

+13  A: 

With standard sh and bash, you can

set -e

It will

$ help set
...
        -e  Exit immediately if a command exits with a non-zero status.

It also works (from what I could gather) with zsh. It also should work for any Bourne shell descendant.

With csh/tcsh, you have to launch your script with #!/bin/csh -e

mat
Thanks, this seems to be what I want. I should sharpen my Google fu, I guess... :)
Pistos
Note that commands in conditionals can fail without causing the script to exit - which is crucial. For example: if grep something /some/where; then : it was found; else : it was not found; fi works fine, regardless of whether something is found in /some/where.
Jonathan Leffler
A: 

May be you could use:

$ <any_command> || exit 1
Barun