Convert decimal to hexadecimal in UNIX shell script

Question

In a UNIX shell script, what can I use to convert decimal numbers into hexadecimal? I thought od would do the trick, but it's not realizing I'm feeding it ASCII representations of numbers.

printf? Gross! Using it for now, but what else is available? :)

Answer 1

Tried printf(1)?

printf "%x\n" 34
22

There are probably ways of doing that with builtin functions in all shells but it would be less portable. I've not checked the POSIX sh specs to see whether it has such capabilities.

Answer 2

try

printf "%X\n" ${MY_NUMBER}

HTH

cheers,

Rob

Answer 3

echo "obase=16; 34" | bc

If you want to filter a whole file of integers, one per line:

( echo "obase=16" ; cat file_of_integers ) | bc

Answer 4

Which shell are you using? In zsh you can do this sort of thing:

% typeset -i 16 y
% print $(( [#8] x = 32, y = 32 ))
8#40
% print $x $y
8#40 16#20
% setopt c_bases
% print $y
0x20

(Example taken from documentation.)

I believe bash has similar capabilities.

Answer 5

I use this:

$ echo $((0xfee10000))

Answer 6

Sorry my fault, try this...

#!/bin/bash
:

declare -r HEX_DIGITS="0123456789ABCDEF"

dec_value=$1
hex_value=""

until [ $dec_value == 0 ]; do

    rem_value=$((dec_value % 16))
    dec_value=$((dec_value / 16))

    hex_digit=${HEX_DIGITS:$rem_value:1}

    hex_value="${hex_digit}${hex_value}"

done

echo -e "${hex_value}"

$ ./dtoh 1024

400

Answer 7

watever as if i care