Why such illicit output comes?

Question

Possible Duplicate:
what will be the output & why

#include<stdio.h>

int main()
{
  int a=5,b=10;
  printf("%d %d %d %d %d %d");
  return 0;
}

output: 10 5 0 344 0 0

Answer 1

It will depends of the compiler since the behavior in that case in undefined.

In your case I suppose that the values 10 and 5 where on the stack and that printf, assuming 6 arguments tried to get them and the values on top of the stack where retrieved.