views:

87

answers:

3

I am looking to do something like this. I remember I had some issues with values disappearing when programming like this. Is this type of structure "correct/valid" for a hash?

my %VAR;
$VAR{SCALAR} = "test scalar";
$VAR{ARRAY}[0] = "test array";
$VAR{HASH}{NAME}[0] = "test hash array 1";
$VAR{HASH}{NAME}[1] = "test hash array 2";
$VAR{HASH}{NAME}[2]{SOMEHASH} = "test hash array hash 1";
$VAR{HASH}{NAME}[2]{ANOTHERHASH} = "test hash array hash 2";
+5  A: 

I see no reason why this wouldn't work. What issues are you seeing?

If you want to make sure your data structure looks like what you'd expect, I recommend something like Data::Dumper:

 # set up your %VAR hash as you like
 use Data::Dumper;
 print Dumper(\%VAR);

Should get something like:

$VAR1 = {
      'HASH' => {
                  'NAME' => [
                              'test hash array 1',
                              'test hash array 2',
                              {
                                'ANOTHERHASH' => 'test hash array hash 2',
                                'SOMEHASH' => 'test hash array hash 1'
                              }
                            ]
                },
      'ARRAY' => [
                   'test array'
                 ],
      'SCALAR' => 'test scalar'
    };
zigdon
+1  A: 

This isn't exactly your question, but... if you're actually building the data structure in that fashion, you might consider a cleaner "literal" syntax:

#!/usr/bin/perl
use strict;
use warnings;

my %VAR = (
  SCALAR => 'test scalar',
  ARRAY => [
    'test array',
  ],
  HASH => {
    NAME => [
      'test hash array 1',
      'test hash array 2',
      {
        SOMEHASH => 'test hash array hash 1',
        ANOTHERHASH => 'test hash array hash 2',
      },
    ],
  },
);

The main two reasons are readability and autovivification bugs. That's not incorrect perl, but it can lead to hard-to-debug issues, such as accidentally typing:

$VAR{HASH}{NAME}[1] = "test hash array 1";
$VAR{HASH}{NAME}[2] = "test hash array 2";
$VAR{HASH}{NAME}[2] = "test hash array 3";
$VAR{HASH}{NAME}[4] = "test hash array 4";

instead of

$VAR{HASH}{NAME}[1] = "test hash array 1";
$VAR{HASH}{NAME}[2] = "test hash array 2";
$VAR{HASH}{NAME}[3] = "test hash array 3";
$VAR{HASH}{NAME}[4] = "test hash array 4";

Which can't be an issue if you're using

$VAR{HASH}{NAME} = [
  undef,
  'test hash array 1',
  'test hash array 2',
  'test hash array 3',
  'test hash array 4',
];
Sir Robert
A: 

Often when people complain about disappearing values it's because they replaced them. When you assign to any part of a hash, you replace the value that was there previously even if it was a reference value:

use 5.010;

use Data::Dumper;

my %hash;

$hash{key} = { qw(a 1 b 2) };
say Dumper( \%hash );

$hash{key} = 5;
say Dumper( \%hash );

The output shows that the hash reference that was the second level is no longer there:

$VAR1 = {
          'key' => {
                     'a' => '1',
                     'b' => '2'
                   }
        };

$VAR1 = {
          'key' => 5
        };

You just have to be careful what and where you assign things, just like you do with any other variable.

brian d foy