Finding a strings in a text using regular expressions with Python

Question

Hi, I have a text, in which only <b> and </b> has been used.for example<b>abcd efg-123</b> . Can can I extract the string between these tags? also I need to extract 3 words before and after this chunk of <b>abcd efg-123</b> string. How can I do that? what would be the suitable regular expression for this?

Answer 1

You should not use regexes for HTML parsing. That way madness lies.

The above-linked article actually provides a regex for your problem -- but don't use it.

Answer 2

this will get what's in between the tags,

>>> s="1 2 3<b>abcd efg-123</b>one two three"
>>> for i in s.split("</b>"):
...   if "<b>" in i:
...      print i.split("<b>")[-1]
...
abcd efg-123

Answer 3

This is actually a very dumb version and doesn't allow nested tags.

re.search(r"(\w+)\s+(\w+)\s+(\w+)\s+<b>([^<]+)</b>\s+(\w+)\s+(\w+)\s+(\w+)", text)

See Python documentation.

Answer 4

Handles tags inside the <b> unless they are <b> ofcouse.

import re    
sometext = 'blah blah 1 2 3<b>abcd efg-123</b>word word2 word3 blah blah'
result = re.findall(
      r'(((?:(?:^|\s)+\w+){3}\s*)'            # Match 3 words before
      r'<b>([^<]*|<[^/]|</[^b]|</b[^>])</b>'  # Match <b>...</b>
      r'(\s*(?:\w+(?:\s+|$)){3}))', sometext) # Match 3 words after

result == [(' 1 2 3<b>abcd efg-123</b>word word2 word3 ',
    ' 1 2 3',
    'abcd efg-123',
    'word word2 word3 ')]

This should work, and perform well, but if it gets any more advanced then this you should consider using a html parser.