python promblem(for loops)

Question

Possible Duplicate:
determining a consonant and vowel count in a string

for x in range(length):
            for y in range(x+1,length):
                if "a"<=m[x]<="z" and "a"<=m[y]<="z":
                    i=0
                    count=0
                    for i in range(length):
                        if m[i]=="a" or m[i]=="e" or m[i]=="i" or m[i]=="o" or m[i]=="u" :
                            count=count+1
                            consonants=length-count
                        else:
                            consonants=length-count




                else:

                    print("Input:" + m +" is incorrect! Please try again.")
                    b=True

how can i print else satement for just one time i dont want to keep it go under for loop