Simple "for" question

Question

How can I fix this statement:

for i in LISTA and i not in LISTB:
   print i

Answer 1

for i in LISTA:
  if i not in LISTB:
    print i

Answer 2

new_list = set(LISTA) -  set(LISTB) # if you don't have duplicate
for i in new_list:
   print i

Or :

for i in LISTA:
   if i in LISTB:
      continue
   print i

Answer 3

A more sophisticated solution. This is a simple intersection complement.

a = set([1, 2, 3])
b = set([3, 4, 5])

print(a - b)

Answer 4

for i in (i for i in LISTA if i not in LISTB):
    print i

The part in parentheses is a generator expression. The benefit of this over other methods that is that it doesn't create duplicate (temporary) sets or list objects. This is especially important if LISTA and/or LISTB are really large.