Python function to convert seconds into minutes, hours, and days

Question

Question: Write a program that asks the user to enter a number of seconds, and works as follows:

• There are 60 seconds in a minute. If the number of seconds entered by the user is greater than or equal to 60, the program should display the number of minutes in that many seconds.

• There are 3600 seconds in an hour. If the number of seconds entered by the user is greater than or equal to 3600, the program should display the number of hours in that many seconds.

• There are 86400 seconds in a day. If the number of seconds entered by the user is greater than or equal to 86400, the program should display the number of days in that many seconds.

What I have so far:

def time():
    sec = int( input ('Enter the number of seconds:'.strip())
    if sec <= 60:
        minutes = sec // 60
        print('The number of minutes is {0:.2f}'.format(minutes)) 
    if sec (<= 3600):
        hours = sec // 3600
        print('The number of minutes is {0:.2f}'.format(hours))
    if sec <= 86400:
        days = sec // 86400
        print('The number of minutes is {0:.2f}'.format(days))
    return

Answer 1

Do it the other way round subtracting the secs as needed, and don't call it time, there's a package named that:

def sec_to_time():
    sec = int( input ('Enter the number of seconds:'.strip())

    days = sec / 86400
    sec -= 86400*days

    hrs = sec / 3600
    sec -= 3600*hrs

    mins = sec / 60
    sec -= 60*mins
    print days, ':', hrs, ':', min, ':', sec

Answer 2

This will convert n seconds into d days, h hours, m minutes, and s seconds.

from datetime import datetime, timedelta

def GetTime():
    sec = timedelta(seconds=int(input('Enter the number of seconds: ')))
    d = datetime(1,1,1) + sec

    print("DAYS:HOURS:MIN:SEC")
    print("%d:%d:%d:%d" % (d.day-1, d.hour, d.minute, d.second))