Quickest way to implement a new interface member in many classes?

Question

Do you know a quick way to implement method(s) from an Interface to a Class. If yes, how can you do it?

Situation : I have an Interface used by over 15 concrete classes. I added a new method and I need to implement this new method in all concrete class.

Update

All my concrete class implement the interface and all the method fine. Later, I add a new method in the interface. To be able to compile, I need to implement the new method in all class. I do not want to go 1 by 1 on each class to implement the method. Is there a way, like "Right clicking the new method" in the interface that will go in all concrete class and all automaticly the new method. This way I will not have to open all class?

Answer 1

Provide an abstract base class with a default implementation, and then have all your concrete classes inherit that abstract class.

Answer 2

yes,

immplement the interface class in each of the 15 classes. Example:

public class MyClass:MyInteface{

}

afterwards, Hover over the first letter of the interface name, and select from dropdown "Explicitly implement interface ".

I am assuming you are using Visual Studio.

Answer 3

Since you mentioned that you have ReSharper installed, here some way to quickly implement this:

• Use "Find Usages Advanced" with "Implementations" checkbox checked
• For each class use quick action "Implement members"

Also you can use "solution wide analysis" feature of ReSharper - it will quickly find all classes that don't implement this new method

EDIT:

Finally I found a really quick way:

• Save method signature in clipboard.
• Position cursor on Boo in IFoo interface (notice code error - empty code block, this is intentional).
• Right click and choose Refactor->"Push Members down"
• Select needed classes in the shown dialog box and click Next.

• Restore method signature from clipboard

  internal interface IFoo { void Boo() { } }

  class Boo:IFoo { }

  class Foo: IFoo { }