C# Freely convert between List<T> and IEnumerable<T>

Question

How can I convert a List to an IEnumerable and back again.

The reason I want to do this is to run a series of LINQ statements on the List i.e. sort etc

Answer 1

List<string> myList = new List<string>();
IEnumerable<string> myEnumerable = myList;
List<string> listAgain = myEnumerable.ToList();

Answer 2

Aside: Note that the standard LINQ operators (as per the earlier example) don't change the existing list - list.OrderBy(...).ToList() will create a new list based on the re-ordered sequence. It is pretty easy, however, to create an extension method that allows you to use lambdas with List<T>.Sort:

static void Sort<TSource, TValue>(this List<TSource> list,
    Func<TSource, TValue> selector)
{
    var comparer = Comparer<TValue>.Default;
    list.Sort((x,y) => comparer.Compare(selector(x), selector(y)));
}

static void SortDescending<TSource, TValue>(this List<TSource> list,
    Func<TSource, TValue> selector)
{
    var comparer = Comparer<TValue>.Default;
    list.Sort((x,y) => comparer.Compare(selector(y), selector(x)));
}

Then you can use:

list.Sort(x=>x.SomeProp); // etc

This updates the existing list in the same way that List<T>.Sort usually does.

Answer 3

A List<T> is an IEnumerable<T>, so actually, there's no need to 'convert' a List<T> to an IEnumerable<T>. Since a List<T> is an IEnumerable<T>, you can simply assign a List<T> to a variable of type IEnumerable<T>.

The other way around, not every IEnumerable<T> is a List<T> offcourse, so then you'll have to call the ToList() member method of the IEnumerable<T>.

Answer 4

A List<T> is already an IEnumerable<T>, so you can run LINQ statements directly on your List<T> variable.

If you don't see the LINQ extension methods like OrderBy() I'm guessing it's because you don't have a using System.Linq directive in your source file.

You do need to convert the LINQ expression result back to a List<T> explicitly, though:

List<Customer> list = ...
list = list.OrderBy(customer => customer.Name).ToList()