Floating Point to Binary Value(C++)

Question

I want to take a floating point number in C++, like 2.25125, and a int array filled with the binary value that is used to store the float in memory (IEEE 754).

So I could take a number, and end up with a int num[16] array with the binary value of the float: num[0] would be 1 num[1] would be 1 num[2] would be 0 num[3] would be 1 and so on...

Putting an int into an array isn't difficult, just the process of getting the binary value of a float is where I'm stuck. Can you just read the binary in the memory that the float variable? If not, how could I go about doing this in C++?

EDIT: The reason for doing the comparison this way is that I am wanting to learn to do bitwise operations in C++.

Answer 1

int fl = *(int*)&floatVar; //assuming sizeof(int) = sizeof(float)

int binaryRepresentation[sizeof(float) * 8];

for (int i = 0; i < sizeof(float) * 8; ++i)
    binaryRepresentation[i] = ((1 << i) & fl) != 0 ? 1 : 0;

Explanation

(1 << i) shifts the value 1, i bits to the left. The & operator computes the bitwise and of the operands.

The for loop runs once for each of the 32 bits in the float. Each time, i will be the number of the bit we want to extract the value from. We compute the bitwise and of the number and 1 << i:

Assume the number is: 1001011, and i = 2

1<<i will be equal to 0000100

  10001011
& 00000100
==========
  00000000

if i = 3 then:

  10001011
& 00001000
==========
  00001000

Basically, the result will be a number with ith bit set to the ith bit of the original number and all other bits are zero. The result will be either zero, which means the ith bit in the original number was zero or nonzero, which means the actual number had the ith bit equal to 1.

Answer 2

Cast the int pointer to a float pointer, and you're done.

(Though I wouldn't declare it as an int array. I'd use void* to make it clear the the memory is being used as a dumping ground for other values.)

Incidentally, why don't you just use an array of floats?

Answer 3

If you need a particular floating point representation, you'll have to build that up semantically from the float itself, not by bit-copying.

c0x standard: http://c0x.coding-guidelines.com/5.2.4.2.2.html doesn't define the format of floating point numbers.

Answer 4

Can you just read the binary in the memory that the float variable?

Yes. Static cast a pointer to it to an int pointer and read the bits from the result. An IEEE 754 float is 32 bits.

Answer 5

Create a union of float and and unsigned long. set the value of the float member and iterate over the bits of the unsigned long value as already described in other answers.

This will eliminate the cast operators.

Answer 6

You can use an unsigned char to read the float byte by byte into the integer array:

unsigned int bits[sizeof (float) * CHAR_BIT];
unsigned char const *c = static_cast<unsigned char const*>(
    static_cast<void const*>(&my_float)
);

for(size_t i = 0; i < sizeof(float) * CHAR_BIT; i++) {
    int bitnr = i % CHAR_BIT;
    bits[i] = (*c >> bitnr) & 1;
    if(bitnr == CHAR_BIT-1)
        c++;
}

// the bits are now stored in "bits". one bit in one integer.

By the way, if you just want to compare the bits (as you comment on another answer) use memcmp:

memcmp(&float1, &float2, sizeof (float));

Answer 7

Use union and bitset:

#include <iostream>
#include <bitset>

int main()
{
    union
    {
         float input;   // assumes sizeof(float) == sizeof(int)
         int   output;
    }    data;

    data.input = 2.25125;

    std::bitset<sizeof(float) * CHAR_BIT>   bits(data.output);


    std::cout << bits << std::endl;

    // or

    std::cout << "BIT 4: " << bits[4] << std::endl;
    std::cout << "BIT 7: " << bits[7] << std::endl;
}

It may not be an array but you can access bits with [] operator as if you were using an array.

Output

$ ./bits
01000000000100000001010001111011
BIT 4: 1
BIT 7: 0

Answer 8

Looking at the comments in this answer (http://stackoverflow.com/questions/474007/floating-point-to-binary-valuec#474014) the reason to do this is to perform a bitwise comparison of two values.

#include <iostream>

int main()
{
    union Flip
    {
         float input;   // assumes sizeof(float) == sizeof(int)
         int   output;
    };

    Flip    data1;
    Flip    data2;
    Flip    data3;

    data1.input = 2.25125;
    data2.input = 2.25126;
    data3.input = 2.25125;

    bool    test12  = data1.output ^ data2.output;
    bool    test13  = data1.output ^ data3.output;
    bool    test23  = data2.output ^ data3.output;

    std::cout << "T1(" << test12 << ") T2(" << test13 << ") T3(" << test23 << ")\n";


}

Answer 9

Easiest way:

float myfloat;
file.read((char*)(&myfloat),sizeof(float));

Answer 10

code float 2 binary in c++. example: input float=5.25 output binary= 0000000000000101 0000000000000001