xslt hyperlink, separate the url and descption

Question

I have a list in sharepoint with a hyperlink column.

I'm putting this list into xml and applying xslt to it.

the xml is producing output in the form of:

<link>http://www.foo.com, http://www.foo.com&lt;/link&gt;

how can i display this link using xslt?

thanks

Answer 1

How about:

<xsl:template match="link">
  <a href="{substring-before(.,',')}">
    <xsl:value-of select="substring-after(.,',')"/>
  </a>
</xsl:template>

Answer 2

For XSLT 2.0

<xsl:template match="link">
    <xsl:element name="a">
      <xsl:attribute name="href">
         <xsl:value-of select="substring-before(.,',')"/>
      </xsl:attribute>
         <xsl:value-of select="substring-after(.,',')"/>
     </xsl:element>
 </xsl:template>

Although it makes it slightly less readable, the extended syntax is considered good practice when stylesheets become large. Literal Result Elements are not as easy to manipulate via XPath as xsl:element/xsl:attribute