tags:

views:

3239

answers:

8

Is it possible to just declaring a variable in Python, like so?:

var

so that it's gonna be initialized to None?

It seems like python allows this, but as soon as you access it, it crashes.

Is this possible? If not, why?

EDIT: I wanna do this for cases like this:

value

for index in sequence:

   if value == None and conditionMet:
       value = index
       break

Duplicate

Related

+13  A: 

Why not just do this:

var = None

Python is dynamic, so you don't need to declare things; they exist automatically in the first scope where they're assigned. So, all you need is a regular old assignment statement as above.

This is nice, because you'll never end up with an uninitialized variable. But be careful -- this doesn't mean that you won't end up with incorrectly initialized variables. If you init something to None, make sure that's what you really want, and assign something more meaningful if you can.

tgamblin
I was gonna do that, but just thought implicitly it would do that.
Joan Venge
The point is for this to be explicit, not implicit. No guessing what the initial value is. No wondering if an uninitialized variable throws an exception or magically has a useful value.
S.Lott
+3  A: 

I'm not sure what you're trying to do. Python is a very dynamic language; you don't usually need to declare variables until you're actually going to assign to or use them. I think what you want to do is just

foo = None

which will assign the value None to the variable foo.

EDIT: What you really seem to want to do is just this:

#note how I don't do *anything* with value here
#we can just start using it right inside the loop

for index in sequence:
   if conditionMet:
       value = index
       break

try:
    doSomething(value)
except NameError:
    print "Didn't find anything"

It's a little difficult to tell if that's really the right style to use from such a short code example, but it is a more "Pythonic" way to work.

EDIT: below is comment by JFS (posted here to show the code)

Unrelated to the OP's question but the above code can be rewritten as:

for item in sequence:
    if some_condition(item): 
       found = True
       break
else: # no break or len(sequence) == 0
    found = False

if found:
   do_something(item)

NOTE: if some_condition() raises an exception then found is unbound.
NOTE: if len(sequence) == 0 then item is unbound.

The above code is not advisable. Its purpose is to illustrate how local variables work, namely whether "variable" is "defined" could be determined only at runtime in this case. Preferable way:

for item in sequence:
    if some_condition(item):
       do_something(item)
       break

Or

found = False
for item in sequence:
    if some_condition(item):
       found = True
       break

if found:
   do_something(item)
kquinn
Is there a difference between a dynamic language and a very dynamic language?
Gavin Miller
There's a great article explaining the different axes of programming language typing, and how they're continuums, not boolean values; unfortunately I can never find that article again when I want to cite it :( I consider Python "very dynamic" because it's on the far end of multiple axes.
kquinn
I've posted my comment inline to show the code.
J.F. Sebastian
+2  A: 

I usually initialize the variable to something that denotes the type like

var = ""

or

var = 0

If it is going to be an object then don't initialize it until you instantiate it:

var = Var()
Andrew Hare
+6  A: 

I'm heartily recommend to read Other languages have "variables" (that I added as a related link to your question) in 2 minutes you'll know that Python has "names", not "variables".

val = None
# ...
if val is None:
   val = any_object
J.F. Sebastian
That's an excellent article.
Steve Claridge
An important concept to understand.
Bernard
+1  A: 

First of all, my response to the question you've originally asked

Q: How do I discover if a variable is defined at a point in my code?

A: Read up in the source file until you see a line where that variable is defined.

But further, you've given a code example that there are various permutations of that are quite pythonic. You're after a way to scan a sequence for elements that match a condition, so here are some solutions:

def findFirstMatch(sequence):
    for value in sequence:
        if matchCondition(value):
            return value

    raise LookupError("Could not find match in sequence")

Clearly in this example you could replace the raise with a return None depending on what you wanted to achieve.

If you wanted everything that matched the condition you could do this:

def findAllMatches(sequence):
    matches = []
    for value in sequence:
        if matchCondition(value):
            matches.append(value)

    return matches

There is another way of doing this with yield that I won't bother showing you, because it's quite complicated in the way that it works.

Further, there is a one line way of achieving this:

all_matches = [value for value in sequence if matchCondition(value)]
Jerub
+1  A: 

You look like you're trying to write C in Python. If you want to find something in a sequence, Python has builtin functions to do that, like

value = sequence.index(blarg)
+1  A: 

If I'm understanding your example right, you don't need to refer to 'value' in the if statement anyway. You're breaking out of the loop as soon as it could be set to anything.

value = None
for index in sequence:
   doSomethingHere
   if conditionMet:
       value = index
       break
fholo
A: 

Well, if you want to check if a variable is defined or not then why not check if its in the locals() or globals() arrays? Your code rewritten:

for index in sequence:
   if 'value' not in globals() and conditionMet:
       value = index
       break

If it's a local variable you are looking for then replace globals() with locals().

Johan