I have something like this:
$('#output').xslt({xml: 'x',xslUrl: 'Test.xsl'});
How do I pass a parameter to the Test.xsl file and retreive the same url in the xsl file?
I am using the jquery libraries: jquery.1.1.3.js
and jquery.xslt.js
Or is there any way I could send a parameter to my xsl file via js or jQuery ?