Timing concurrent processes in bash with 'time'

Question

Is there a simple way to do the equivalent of this, but run the two processes concurrently with bash?

$ time sleep 5; sleep 8

time should report a total of 8 seconds (or the amount of time of the longest task)

Answer 1

time sleep 8 & time sleep 5

The & operator causes the first command to run in the background, which practically means that the two commands will run concurrently.

Answer 2

Using sleeps as examples.

If you want to only time the first process, then

time sleep 10 & sleep 20

If you want to time both processes, then

time (sleep 10 & sleep 20)

Answer 3

Sorry my question may not have been exactly clear the first time around, but I think I've found an answer, thanks to some direction given here.

time sleep 5& time sleep 8

will time both processes while they run concurrently, then I'll just take the larger result.

Answer 4

$ time (sleep 5 & sleep 8 & wait)

real    0m8.019s
user    0m0.005s
sys     0m0.005s

Without any arguments, the shell built-in wait waits for all backgrounded jobs to complete.