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Question

.NET XML Serialization without <?xml> root node

Answer 1

+1 A:

try DataContractSerializer.

ArsenMkrt 2009-06-01 05:37:11

Thanks, any ideas for .NET 2.0 though?

Graphain 2009-06-01 05:43:42

@ArsenMkrt: how would that have helped? -1.

John Saunders 2009-07-31 01:47:13

@John DataContractSeializer doesn't create header <?xml..., so he could serialize each object by this class

ArsenMkrt 2009-07-31 03:35:48

@ArsenMkrt: `DataContractSerializer` also doesn't emit DTD declarations.

John Saunders 2010-05-28 02:02:39

Answer 2

+14 A:

Never build xml using string concatenation. It's evil.

Output:

<?xml version="1.0" encoding="utf-16"?>
<!DOCTYPE APIRequest SYSTEM "https://url"&gt;
<APIRequest>
  <Head>
    <Key>123</Key>
  </Head>
  <ObjectClass>
    <Field>Value</Field>
  </ObjectClass>
</APIRequest>

Code:

using System;
using System.Diagnostics;
using System.Text;
using System.Xml;
using System.Xml.Serialization;

public static class Program {
    public static void Main() {
        var obj = new ObjectClass { Field = "Value" };

        var settings = new XmlWriterSettings {
            Indent = true
        };

        var xml = new StringBuilder();
        using (var writer = XmlWriter.Create(xml, settings)) {
            Debug.Assert(writer != null);

            writer.WriteDocType("APIRequest", null, "https://url", null);
            writer.WriteStartElement("APIRequest");
            writer.WriteStartElement("Head");
            writer.WriteElementString("Key", "123");
            writer.WriteEndElement(); // </Head>

            var nsSerializer = new XmlSerializerNamespaces();
            nsSerializer.Add("", "");

            var xmlSerializer = new XmlSerializer(obj.GetType(), "");
            xmlSerializer.Serialize(writer, obj, nsSerializer);

            writer.WriteEndElement(); // </APIRequest>
        }

        Console.WriteLine(xml.ToString());
        Console.ReadLine();
    }
}

[XmlRoot("ObjectClass")]
public class ObjectClass {
    [XmlElement("Field")]
    public string Field { get; set; }
}

Simon Svensson 2009-06-01 05:54:18

Thanks, I knew the string concat was bad but I thought it would at least work - I guess not! Thanks :-)

Graphain 2009-06-01 06:01:49

Just checked - thanks heaps!

Graphain 2009-06-01 06:05:19

If I could vote this up more/give a bounty tip easily I would :-)

Graphain 2009-06-01 06:06:20

Answer 3

A:

This link: http://www.eggheadcafe.com/conversation.aspx?messageid=31106520&threadid=31106516 talks about the same issue with the best conlusion being manual removal of the header so better solutions are welcome!

Graphain 2009-06-01 06:00:06

Answer 4

A:

Derive your own XmlTextWriter to omit the XML declaration.

Private Class MyXmlTextWriter
Inherits XmlTextWriter
Sub New(ByVal sb As StringBuilder)
 MyBase.New(New StringWriter(sb))
End Sub
Sub New(ByVal w As TextWriter)
 MyBase.New(w)
End Sub

Public Overrides Sub WriteStartDocument()
 ' Don't emit XML declaration
End Sub
Public Overrides Sub WriteStartDocument(ByVal standalone As Boolean)
 ' Don't emit XML declaration
End Sub
End Class

Call Serialize with an instance of the derived MyXmlTextWriter.

Dim tw As New MyXmlTextWriter(sb)
Dim objXmlSerializer As New XmlSerializer(type)
objXmlSerializer.Serialize(tw, obj)

Doug D 2009-06-05 12:33:50

@Doug D: I have trouble believing you consider this to be a better solution.

John Saunders 2009-07-31 01:48:17

Answer 5

A:

Scott Hanselman's got a good post on this. I used Kzu's example (which Scott's blog points to) a while back for the same thing and it worked great.

Tone 2009-07-31 01:37:50

@Tone: kind of a meee-tooo? It's just what Doug D said a month ago. -1.

John Saunders 2009-07-31 01:50:10

Answer 6

A:

One liner, to remove the first line from a string:

String.Join("\n", strXML.Split('\n').Skip(1).ToArray())

Not elegant, but concise.

2010-01-14 13:19:46

-1: how does it help?

John Saunders 2010-01-15 04:05:56

Answer 7

A:

The two-line answer is: use an XmlWriterSettings object with the OmitXmlDeclaration property to True -- pass the settings object as the second parameter when you create your XmlWriter.

tswaters 2010-05-28 01:24:45

-1: Nonsense. Read the question.

John Saunders 2010-05-28 02:01:17

Answer 8

+2 A:

try this:

internal static string ToXml(object obj)
{
  string retval = null;
  if (obj != null)
  {
    StringBuilder sb = new StringBuilder();
    using(XmlWriter writer = XmlWriter.Create(sb, new XmlWriterSettings() { OmitXmlDeclaration = true }))
    {
      new XmlSerializer(obj.GetType()).Serialize(writer, obj);
    }
    retval = sb.ToString();
  }
  return retval;
}

Giuseppe Dimauro

Giuseppe Dimauro 2010-09-17 08:21:49

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.NET XML Serialization without <?xml> root node

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