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2019

answers:

5

I want to do something that seems fairly simple... I get results but the problem is, I have no way to know if the results are correct.

I'm working in C and I have two pointers; I want to print the contents of the pointer. I don't want to dereference the pointer to get the value pointed at, I just want the address that the pointer has stored.

I wrote the following code and what I need to know is if it is right and if not, how can I correct it.

/* item one is a parameter and it comes in as: const void* item1   */
const Emp* emp1 = (const Emp*) item1; 

printf("\n comp1-> emp1 = %p; item1 = %p \n", emp1, item1 );

While I'm posting this (and the reason it is important that it is correct) is that I eventually need to do this for a pointer-to-a-pointer. That is:

const Emp** emp1 = (const Emp**) item1;

Thank you!

Regards,
Frank

+3  A: 

What you have is correct. Of course, you'll see that emp1 and item1 have the same pointer value.

Don Neufeld
I do expect that, thanks.
Frank V
They won't be the same if item1's type is part of a multiple inheritance and/or is an ancestor of Emp, depending on how the compiler lays out each of the classes that compose item1's type.
Jim Buck
@Jim: The "C" tag suggests otherwise
Hasturkun
@Jim: Hasturkun is right. I'm working in C. I should have posted that.
Frank V
+3  A: 

To print address in pointer to pointer:

printf("%p",emp1)

to dereference once and print the second address:

printf("%p",*emp1)

You can always verify with debugger, if you are on linux use ddd and display memory, or just plain gdb, you will see the memory address so you can compare with the values in your pointers.

stefanB
that's the same as in the code Frank posted.
Luca Matteis
well I thought he asked if it is correct ...
stefanB
+2  A: 

Since you already seem to have solved the basic pointer address display, here's how you would check the address of a double pointer:

char **a;
char *b;
char c = 'H';

b = &c;
a = &b;

You would be able to access the address of the double pointer a by doing:

printf("a points at this memory location: %p", a);
printf("which points at this other memory location: %p", *a);
Luca Matteis
A: 

I believe this would be most correct.

printf("%p", (void *)emp1);
printf("%p", (void*)*emp1);

printf() is a variadic function and must be passed arguments of the right types. The standard says %p takes void *.

sigjuice
A: 

I have been in this position, especially with new hardware. I suggest you write a little hex dump routine of your own. You will be able to see the data, and the addresses they are at, shown all together. It's good practice and a confidence builder.

gbarry
at the expense of sounding ignorant - could you elaborate on how one writes such a routine?
Faisal Vali