The other answers may not give the type of output that you're looking for, because instead of giving a string of years, months, etc., the Rails helpers just show the largest unit. If you're looking for something more broken down, here's another option. Stick this method into a helper:
def time_diff_in_natural_language(from_time, to_time)
from_time = from_time.to_time if from_time.respond_to?(:to_time)
to_time = to_time.to_time if to_time.respond_to?(:to_time)
distance_in_seconds = ((to_time - from_time).abs).round
components = []
%w(year month week day).each do |interval|
# For each interval type, if the amount of time remaining is greater than
# one unit, calculate how many units fit into the remaining time.
if distance_in_seconds >= 1.send(interval)
delta = (distance_in_seconds / 1.send(interval)).floor
distance_in_seconds -= delta.send(interval)
components << pluralize(delta, interval)
end
end
components.join(", ")
end
And then in a view you can say something like:
<%= time_diff_in_natural_language(Time.now, 2.5.years.ago) %>
=> 2 years, 6 months, 2 days
The given method only goes down to days, but can be easily extended to add in smaller units if desired.