Replacing all occurrences of a string in javascript?

Question

Say I have this string:

Test abc test test abc test test
test abc test test abc

Doing

str=str.replace('abc','');

Seems only to remove the first occurrence of abc in the string above. How can I replace ALL occurrences of it?

Answer 1

str = str.replace(/abc/g, '');

In response to comment:

var find = 'abc';
var re = new RegExp(find, 'g');

str = str.replace(re, '');

In response to Click Upvote's comment, you could simplify it even more:

function replaceAll(find, replace, str) {
  return str.replace(new RegExp(find, 'g'), replace);
}

Answer 2

str = str.replace(/abc/g, '');

Or try the replaceAll function from here:

http://stackoverflow.com/questions/1137436/useful-javascript-methods-that-extends-built-in-objects/1137579#1137579

str = str.replaceAll('abc', ''); OR

var search = 'abc';
str = str.replaceAll(search, '');

EDIT: Clarification about replaceAll availability

The 'replaceAll' method is added to String's prototype. This means it will be available for all string objects/literals.

E.g.

var output = "test this".replaceAll('this', 'that');  //output is 'test that'.
output = output.replaceAll('that', 'this'); //output is 'test this'

Answer 3

use a regex:

str.replace(/abc/g, '');

Answer 4

You could try using your existing code, then throw it in a while loop... Not sure what this will do for performance, but it will definitely get the job done!

var exists = false;
if (str.indexOf('abc') > 0)
    exists = true; // does 'abc' exist in my string?

while (exists) // replace 'abc' as long as it exists
{
    str = str.replace('abc', '');

    if (str.indexOf('abc') > 0)
        exists = true;
    else
        exists = false;
}

Answer 5

As an alternative to regular expressions for a simple literal string, you could use

str = "Test abc test test abc test...".split("abc").join("");

The general pattern is

string.split(search).join(replacement)

I would wrap it in a function so it's more obvious what's going on.