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views:

94

answers:

2

Having found out how to find PHP problems. I am now trying to solve them, but I have no clue on this one.

I made use of mysql_error and I have found:

1054: Unknown column 'o.user_id' in 'on clause'

Is there something wrong with this:

$sql="SELECT o.*, u.user_name, u.email, od.artist_id,cm.nexchange_price

      FROM ".$tableprefix."orders o,".$tableprefix."currency_master cm

     INNER JOIN ".$tableprefix."users u ON o.user_id = u.user_id

     INNER JOIN ".$tableprefix."order_details od ON o.order_id = od.order_id

     WHERE o.order_id = ".GetSQLValueString($orderid,"text")."

      AND o.vorder_currency = cm.vcurrency_code ".$qryopt . " ORDER BY o.order_date DESC";

That column exists in the orders table?!

A: 

Perhaps tableprefix is messing you up. What is the value of variable $sql before you run the query?

joeslice
+4  A: 

You have a comma after "orders o,", which means that you are trying to join the currency_master table with the users table, instead of orders and users. I suppose you wanted to have:

$sql="
  SELECT
    o.*, u.user_name, u.email, od.artist_id,cm.nexchange_price
  FROM
    ".$tableprefix."currency_master cm,
    ".$tableprefix."orders o
  INNER JOIN
    ".$tableprefix."users u
  ON
    o.user_id = u.user_id // et cetera"
JG
Thank you very much! Worked perfectly! :)
Abs