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jquery ajax callback function without dynamic parameters

Answer 1

+1 A:

The solution is so sadly mundane: you needed to add var in front of your variables to declare them as new. They were being overwritten inappropriately by the next iteration before the first one could complete. This code works for me:

save = function(o,i){
    var itt = $(o)
    var tmp = {'desc':itt.html()};
    $.get('ajax/update_post', {'data':array2json(tmp)}, function(a){
        alert(itt.attr('id'))
        updatePostBack(a,itt)
    })
}

updatePostBack = function(a,item){
    alert(item.attr('id'))
}

$.map($("#test > div"), save);

I also moved the map statement to the end so that it's calling the save function after it's been declared.

Gabriel Hurley 2009-07-25 20:56:07

ok, I tested this solution and it certainly is. thank you a lot, Javascript Lord u.u

dnuske 2009-07-25 21:28:08

np, glad I could help.

Gabriel Hurley 2009-07-25 22:08:17

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jquery ajax callback function without dynamic parameters

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