You cannot do it with SQL
(except with dynamic queries), unless you know the number of columns (i. e. questions) in design time.
You should pull the data you want in tabular format and then process it on client side:
SELECT *
FROM Question
LEFT OUTER JOIN
Response
ON Response.QuestionId = Question.QuestionID
or, probably, this (in SQL Server 2005+
, Oracle 8i+
and PostgreSQL 8.4+
):
SELECT *
FROM (
SELECT q.*, ROW_NUMBER() OVER (ORDER BY questionID) AS rn
FROM Question q
) q
LEFT OUTER JOIN
(
SELECT r.*, ROW_NUMBER() OVER (PARTITION BY questionID ORDER BY ResponseID) AS rn
FROM Response r
) r
ON r.QuestionId = q.QuestionID
AND q.rn = r.rn
ORDER BY
q.rn, q.QuestionID
The latter query will give you results in this form (provided you have 4
questions):
rn question response
--- --- ---
1 Question 1 Response 1.1
1 Question 2 Response 2.1
1 Question 3 Response 3.1
1 Question 4 Response 4.1
2 Question 1 Response 1.2
2 Question 2 Response 2.2
2 Question 3 NULL
2 Question 4 Response 4.2
3 Question 1 NULL
3 Question 2 NULL
3 Question 3 Response 3.3
3 Question 4 NULL
, this is it will output the data in tabular form, with rn
marking the row number.
Each time you see the rn
changing on the client, you just close <tr>
and open the new one.
You may safely put your <td>
's one per resultset row, since same number or rows is guaranteed to be returned for each rn
This is quite a frequently asked question.
SQL
just not a right tool to return data with dynamic number of columns.
SQL
operates on sets, and the column layout is an implicit property of a set.
You should define the layout of the set you want to get in design time, just like you define the datatype of a varible in C
.
C
works with strictly defined variables, SQL
works with strictly defined sets.
Note that I'm not saying it's the best method possible. It's just the way SQL
works.
Update:
In SQL Server
, you can pull the table in HTML
form right out of the database:
WITH a AS
(
SELECT a.*, ROW_NUMBER() OVER (PARTITION BY question_id ORDER BY id) AS rn
FROM answer a
),
rows AS (
SELECT ROW_NUMBER() OVER (ORDER BY id) AS rn
FROM answer a
WHERE question_id =
(
SELECT TOP 1 question_id
FROM answer a
GROUP BY
question_id
ORDER BY
COUNT(*) DESC
)
)
SELECT (
SELECT COALESCE(a.value, '')
FROM question q
LEFT JOIN
a
ON a.rn = rows.rn
AND a.question_id = q.id
FOR XML PATH ('td'), TYPE
) AS tr
FROM rows
FOR XML PATH(''), ROOT('table')
See this entry in my blog for more detail: