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3830

answers:

4

What is the simplest way to determine the length (in seconds) of a given mp3 file, without using outside libraries? (python source highly appreciated)

+6  A: 

You can use pymad. It's an external library, but don't fall for the Not Invented Here trap. Any particular reason you don't want any external libraries?

import mad

mf = mad.MadFile("foo.mp3")
track_length_in_milliseconds = mf.total_time()

Spotted here.

--

If you really don't want to use an external library, have a look here and check out how he's done it. Warning: it's complicated.

Harley
I agree with recommending the external library. I haven't used it (or Python for that matter). But I once tried to write, in C++ a program that could simply play MP3s. That didn't pan out, but I did get far enough in to determine the duration of the file. I thought about refactoring that code to ...
Matt Blaine
... post here, but it's pretty darn convoluted. (And in C++, not Python). Not even remotely simple.
Matt Blaine
A: 

You might count the number of frames in the file. Each frame has a start code, although I can't recollect the exact value of the start code and I don't have MPEG specs laying around. Each frame has a certain length, around 40ms for MPEG1 layer II.

This method works for CBR-files (Constant Bit Rate), how VBR-files work is a completely different story.

From the document below:

For Layer I files us this formula:

FrameLengthInBytes = (12 * BitRate / SampleRate + Padding) * 4

For Layer II & III files use this formula:

FrameLengthInBytes = 144 * BitRate / SampleRate + Padding

Information about MPEG Audio Frame Header

Mats Wiklander
I believe the length is 26ms.
Ori Pessach
That sounds familiar.
Mats Wiklander
A: 

Try these links

1.PyMedia
2.MP3Info

Second link spotted here

vikramjb
+4  A: 

Simple, parse MP3 binary blob to calculate something, in Python

That sounds like a pretty tall order. I don't know Python, but here's some code I've refactored from another program I once tried to write.

Note: It's in C++ (sorry, it's what I've got). Also, as-is, it'll only handle constant bit rate MPEG 1 Audio Layer 3 files. That should cover most, but I can't make any guarantee as to this working in all situations. Hopefully this does what you want, and hopefully refactoring it into Python is easier than doing it from scratch.

// determines the duration, in seconds, of an MP3;
// assumes MPEG 1 (not 2 or 2.5) Audio Layer 3 (not 1 or 2)
// constant bit rate (not variable)

#include <iostream>
#include <fstream>
#include <cstdlib>

using namespace std;

//Bitrates, assuming MPEG 1 Audio Layer 3
const int bitrates[16] = {
         0,  32000,  40000,  48000,  56000,  64000,  80000,   96000,
    112000, 128000, 160000, 192000, 224000, 256000, 320000,       0
  };


//Intel processors are little-endian;
//search Google or see: http://en.wikipedia.org/wiki/Endian
int reverse(int i)
{
    int toReturn = 0;
    toReturn |= ((i & 0x000000FF) << 24);
    toReturn |= ((i & 0x0000FF00) << 8);
    toReturn |= ((i & 0x00FF0000) >> 8);
    toReturn |= ((i & 0xFF000000) >> 24);
    return toReturn;
}

//In short, data in ID3v2 tags are stored as
//"syncsafe integers". This is so the tag info
//isn't mistaken for audio data, and attempted to
//be "played". For more info, have fun Googling it.
int syncsafe(int i)
{
 int toReturn = 0;
 toReturn |= ((i & 0x7F000000) >> 24);
 toReturn |= ((i & 0x007F0000) >>  9);
 toReturn |= ((i & 0x00007F00) <<  6);
 toReturn |= ((i & 0x0000007F) << 21);
 return toReturn;     
}

//How much room does ID3 version 1 tag info
//take up at the end of this file (if any)?
int id3v1size(ifstream& infile)
{
   streampos savePos = infile.tellg(); 

   //get to 128 bytes from file end
   infile.seekg(0, ios::end);
   streampos length = infile.tellg() - (streampos)128;
   infile.seekg(length);

   int size;
   char buffer[3] = {0};
   infile.read(buffer, 3);
   if( buffer[0] == 'T' && buffer[1] == 'A' && buffer[2] == 'G' )
     size = 128; //found tag data
   else
     size = 0; //nothing there

   infile.seekg(savePos);

   return size;

}

//how much room does ID3 version 2 tag info
//take up at the beginning of this file (if any)
int id3v2size(ifstream& infile)
{
   streampos savePos = infile.tellg(); 
   infile.seekg(0, ios::beg);

   char buffer[6] = {0};
   infile.read(buffer, 6);
   if( buffer[0] != 'I' || buffer[1] != 'D' || buffer[2] != '3' )
   {   
       //no tag data
       infile.seekg(savePos);
       return 0;
   }

   int size = 0;
   infile.read(reinterpret_cast<char*>(&size), sizeof(size));
   size = syncsafe(size);

   infile.seekg(savePos);
   //"size" doesn't include the 10 byte ID3v2 header
   return size + 10;
}

int main(int argCount, char* argValues[])
{
  //you'll have to change this
  ifstream infile("C:/Music/Bush - Comedown.mp3", ios::binary);

  if(!infile.is_open())
  {
   infile.close();
   cout << "Error opening file" << endl;
   system("PAUSE");
   return 0;
  }

  //determine beginning and end of primary frame data (not ID3 tags)
  infile.seekg(0, ios::end);
  streampos dataEnd = infile.tellg();

  infile.seekg(0, ios::beg);
  streampos dataBegin = 0;

  dataEnd -= id3v1size(infile);
  dataBegin += id3v2size(infile);

  infile.seekg(dataBegin,ios::beg);

  //determine bitrate based on header for first frame of audio data
  int headerBytes = 0;
  infile.read(reinterpret_cast<char*>(&headerBytes),sizeof(headerBytes));

  headerBytes = reverse(headerBytes);
  int bitrate = bitrates[(int)((headerBytes >> 12) & 0xF)];

  //calculate duration, in seconds
  int duration = (dataEnd - dataBegin)/(bitrate/8);

  infile.close();

  //print duration in minutes : seconds
  cout << duration/60 << ":" << duration%60 << endl;

  system("PAUSE");
  return 0;
}
Matt Blaine
I don't think this will work for VBR files.
Ori Pessach
This works perfectly for something I'm building right now, since I don't need VBR support. All I needed to change was the bitrate since it was assuming 56k when the files were 32k (output from LAME).
alxp
I know, I said it was only good for constant bit rate files.
Matt Blaine