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Why is this JSON not being parsed correctly?

Answer 1

+1 A:

Is it because of the wrong content-type? The URL you gave gives a content-type of "text/html". The correct type is application/json. See this.

[Edit] Are you sure your php handles POST? I just wrote a simple HTML which posted to your page and it returned blank.

Here is the HTML

<html><head>
<body>
    <form method="post" action="http://www.my-clock.net/vodafone/getCinema.php"&gt;
     <input type="text" name="cinemaid" value="W5">
     <input type="submit">
    </form>
</body>
</html>

Chetan Sastry 2009-07-29 00:09:34

already added it and it doesn't solve the problem also

fmsf 2009-07-29 00:11:42

I've added in the php script header('content-type: application/json'); and it still doesn't solve it

fmsf 2009-07-29 00:12:25

I'm just keeping it as text/html to be easier to open with the browser, my localhost version is application/json

fmsf 2009-07-29 00:13:17

yeah it does handle post. sry that version online is using get instead of post.

fmsf 2009-07-29 00:34:14

Answer 2

+6 A:

It's because there are line breaks in your strings. If you view the source of the JSON page, you can see them all. If you remove them, the page will work.

Check out:

http://jsbin.com/umidu (with the data cleaned up -- all I did was remove all linebreaks)
http://jsbin.com/ijuhi/ (with the data with linebreaks in it)

Also, you can verify your JSON is invalid by navigating to the URL in your post, viewing the source and copying and pasting it into jslint.

seth 2009-07-29 00:16:42

yeah you're right, you'll get the correct answer. Just a last question, how do you remove the line breaks in php? the str_replace("\n", "", $string); doesn't seem to be working

fmsf 2009-07-29 00:45:15

I've used something line this `$line = ereg_replace("/\n\r|\r\n|\n|\r/", "", $line);`

seth 2009-07-29 00:53:03

it works ty. You'll get the correct answer in 2 days

fmsf 2009-07-29 02:00:42

Alternatively, if you want to encode your line breaks rather than simply remove them: `$line = str_replace("\n", "\\n", str_replace("\r", "\\r", $line));`

Ben Blank 2009-08-01 00:35:35

Answer 3

A:

Are you properly encoding this in your php script?

It appears that alert(data) returns an object because it is a valid string. alert(data.horas[0].hora gives you undefined because that object isn't being interpreted as JSON (e.g. an array of hora objects each with a hora property).

Try this in your php:

<?php echo json_encode(... your array of hora objects here ...); ?>

wgpubs 2009-07-29 00:33:56

if it was only a valid string the alert(data) would output the data.

fmsf 2009-07-29 00:39:50

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