How can I use Zend Layout with Zend View if I call the view from a model?

Question

Basically, I want to render a view and layout from a model. Don't ask me why.

First of all, the views work as intended and I'm loading them into a variable for my perverse use later on. I am also fully aware that I could always do partial scripts. It seems to be a valid fallback, but it just doesn't cut it.

What I want to do is to get the layout to work automatically just like in the case with controllers and views.

Right now I employ something like this:

// Class blablabla
$layout = new Zend_Layout();
$layout->enableLayout();
$layout->setView($view);

// Ugly url, I know, I'm experimenting and they work
$body = $layout->render('mailer/layout/mail');
$body .= $view->render('mailer/templates/' . $type . '.phtml');

The problem is that $body contains the layout and only then the actual view. Any advice? What am I doing wrong?

Answer 1

I think my first note would have to be that you're trying to use a hammer as a screwdriver. As I'm sure you know, in the MVC model the view is the rendering, and is logically distinct (separate) from the model. I'm not sure you're going to find a happy solution to this, since you're crossing the streams.

Answer 2

http://www.wowww.ch/index.php?post/2009/03/16/Zend-Mail-avec-template-standardise-avec-Zend-Layout-et-Zend-View