how to generate the snippet like generated by google with PHP and MySQL?

Question

Say,it just returns the snippet around which the searching keyword exists.

And part of the text is replaced by "...".

Is it possible to achieve that goal with PHP and MySQL?

Answer 1

Can you be more specific? I have no idea what you're asking for.

Answer 2

Probably you'll find your answer here - http://stackoverflow.com/questions/1226272/mysql-conditional-short-descriptions

Answer 3

$snippet = "//mysql query";

function trimmer($updates,$wrds){
if(strlen($updates)<=$wrds){
return $updates;
}else{
$marker = strrpos(substr($updates,0,$wrds),' ');
$string = substr(substr($updates,0,$wrds),0,$marker)."...";return $string;

}

echo trimmer($snippet,200);//You can send the snippet string to this function it searches for the last space if string length is greater than 200 and adds "..." to it

*This is probably what you want(EDIT)

$string1="Lorem Ipsum is simply dummy text of the printing and typesetting industry. Lorem Ipsum has been the industry's standard dummy text ever since the 1500s, when an unknown printer took a galley of type and scrambled it to make a type specimen book.";
function trimmer($updates,$wrds,$pos){
if(strlen($updates)<=$wrds){
return $updates;
}else{
$marker = strrpos(substr($updates,$pos,$wrds),' ');
$string = substr(substr($updates,$pos,$wrds),0,$marker)."...";
 return $string;
}
}
$pos = strpos($string1, "dummy");
echo trimmer($string1,100,$pos);

Answer 4

function excerpt($text, $phrase, $radius = 100, $ending = "...") {
    $phraseLen = strlen($phrase);
    if ($radius < $phraseLen) {
        $radius = $phraseLen;
    }

    $pos = strpos(strtolower($text), strtolower($phrase));

    $startPos = 0;
    if ($pos > $radius) {
        $startPos = $pos - $radius;
    }

    $textLen = strlen($text);

    $endPos = $pos + $phraseLen + $radius;
    if ($endPos >= $textLen) {
        $endPos = $textLen;
    }

    $excerpt = substr($text, $startPos, $endPos - $startPos);
    if ($startPos != 0) {
        $excerpt = substr_replace($excerpt, $ending, 0, $phraseLen);
    }

    if ($endPos != $textLen) {
        $excerpt = substr_replace($excerpt, $ending, -$phraseLen);
    }

    return $excerpt;
}

Shamelessly stolen from the Cake TextHelper.

Answer 5

Modified deceze's function slightly to allow multiple phrases. e.g. your phrase can be "testa testb" and if it does not find testa, then it will go to testb.

function excerpt($text, $phrase, $radius = 100, $ending = "...") { 


         $phraseLen = strlen($phrase); 
       if ($radius < $phraseLen) { 
             $radius = $phraseLen; 
         } 

      $phrases = explode (' ',$phrase);

      foreach ($phrases as $phrase) {
       $pos = strpos(strtolower($text), strtolower($phrase)); 
       if ($pos > -1) break;
      }

         $startPos = 0; 
         if ($pos > $radius) { 
             $startPos = $pos - $radius; 
         } 

         $textLen = strlen($text); 

         $endPos = $pos + $phraseLen + $radius; 
         if ($endPos >= $textLen) { 
             $endPos = $textLen; 
         } 

         $excerpt = substr($text, $startPos, $endPos - $startPos); 
         if ($startPos != 0) { 
             $excerpt = substr_replace($excerpt, $ending, 0, $phraseLen); 
         } 

         if ($endPos != $textLen) { 
             $excerpt = substr_replace($excerpt, $ending, -$phraseLen); 
         } 

         return $excerpt; 
   }

Highlight function

function highlight($c,$q){ 
$q=explode(' ',str_replace(array('','\\','+','*','?','[','^',']','$','(',')','{','}','=','!','<','>','|',':','#','-','_'),'',$q));
for($i=0;$i<sizeOf($q);$i++) 
    $c=preg_replace("/($q[$i])(?![^<]*>)/i","<span class=\"highlight\">\${1}</span>",$c);
return $c;}