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Question

Answer 1

A:

A quick and simple solution would be to check the value at the top of your .each function call, and if it's 0 or -1, return (which works like a break in a .each loop).

if ($option.attr('value') == 0 || $option.attr('value') == -1) return;

And for your whole code:

$(function()
{
  $('#test')
    .after( '<div id="option-inputs"></div>' )
    .find( 'option' ).each( function()
    {
      var $option = $(this);
      //new code
      if ($option.attr('value') == 0 || $option.attr('value') == -1) return;

      $option
        .data( '$input', $( '<span>' + $option.text() + ': </span><input><br>').appendTo( '#option-inputs' ).hide() )
        .bind( 'toggle-input', function()
        {
          var $input  = $option.data( '$input' );
          if ( $option[0].selected )
          {
            $input.show();
          } else {
            $input.hide();
          }      
        })
        .bind( 'click', function()
        {
          $(this).siblings().andSelf().trigger( 'toggle-input' );
        })
        .trigger( 'toggle-input' )
      ;
    })
  ;
});

tj111 2009-08-24 20:50:36

Answer 2

A:

You'll need to set up a "initilization" routine for the <select>, so that when it receives new options it can re-setup the linked inputs.

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd"&gt;
<html lang="en">
<head>
<title>test</title>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<script type="text/javascript" src="http://jqueryjs.googlecode.com/files/jquery-1.3.2.min.js"&gt;&lt;/script&gt;
<script type="text/javascript">

$(function()
{
  //  How you manage this data is up to you, this is just an example
  var optionData = {
      1: { 1: "1.1", 2: "1.2", 3: "1.3" }
    , 2: { 1: "2.1", 2: "2.2", 3: "2.3" }
  }
  var $test = $('#test');

  $test.bind( 'init', function()
  {
    $optionInputs = $( '#option-inputs' );
    if ( !$optionInputs.length )
    {
      $optionInputs = $( '<div id="option-inputs"></div>' ).insertAfter( $test );
    }
    $optionInputs.children().remove();
    $test.find( 'option' ).each( function()
    {
      var $option = $(this);
      $option
        .data( '$input', $( '<span>' + $option.text() + ': </span><input><br>').appendTo( $optionInputs ).hide() )
        .bind( 'toggle-input', function()
        { 
          var $input  = $option.data( '$input' );
          if ( $option[0].selected )
          {
            $input.show();
          } else {
            $input.hide();
          }      
        })
        .bind( 'click', function()
        {
          $(this).siblings().andSelf().trigger( 'toggle-input' );
        })
        .trigger( 'toggle-input' )
      ;
    });
  });

  $('#changer').bind( 'change', function()
  {
    var $this = $(this)
      , options = optionData[$this.val()]
      , optionHtml = '';
    ;

    for ( var i in options )
    {
      if ( options.hasOwnProperty( i ) )
      {
        optionHtml += '<option value="' + i + '">' + options[i] + '</option>';
      }
    }
    $test.html( optionHtml ).trigger( 'init' );
  }).trigger( 'change' );
});


</script>

</head>
<body>

<select id="changer">
  <option value="1">Set 1</option>
  <option value="2">Set 2</option>
</select>

<select id="test" multiple="multiple">
</select>

</body>
</html>

Peter Bailey 2009-08-24 22:04:12

I think this is a little more than I wanted. All I want is for the "changer" select to clear the newly created inputs if there is a change made to it.For example, if I select something in the test select, and a new input is created, going back and selecting something in the changer will remove that new input, then create it again if I select something again in the test select.

Dave Hunt 2009-08-25 14:30:28

I'm really missing something, because as best I can tell from your description, that's exactly what this does.

Peter Bailey 2009-08-25 14:44:49

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jQuery triggers in a form

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