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415

answers:

1

I'm trying to write a query that will return ...

  1. Each distinct user id in the accesslog table.

  2. A count of how many distinct ip addresses each userid has accessed the site with, also from the accesslog table.

  3. That userid's name, email address, and company name, from the users table.

I've got 1 and 2, but I'm not sure how to get 3. I suck at joins, I admit. :(

Here's the query I have now:

SELECT DISTINCT userid, COUNT(ipaddress) AS c FROM accesslog WHERE url LIKE 'www.example.com%' and userid != '' GROUP BY userid ORDER BY c desc

How would I JOIN in the other pieces of data that I want?

+2  A: 

You'll need to join to users table and add all its columns to GROUP BY:

SELECT a.userid, u.name, u.email, u.company, COUNT(a.ipaddress) AS c
  FROM accesslog a, USERS u
 WHERE a.userid = u.userid
   AND a.url LIKE 'www.example.com%'
   AND a.userid != ''
GROUP BY a.userid
ORDER BY c desc
ChssPly76
I don't think you'll need 'DISTINCT' as the 'group by' should take care of that.
BoltBait
thanks for your answer. it would have worked if my databases weren't so screwy.
Ian
@BoltBait - you're right; I've just copied / edited Ian's query and forgot to remove it. Will edit.
ChssPly76