How to find the first row not with all cells filled by "&nbsp" with jQuery?

Question

<table id="experiences" cellpadding="0" border="1" width="100%">
    <caption>table name</caption>
    <tr><th>col1</th><th>col2</th><th>col3</th><th>col4</th><th>col5</th><th>col6</th></tr>
    <tr><td>something</td><td>something</td><td>something</td><td>something</td><td>something</td><td>something</td></tr>
    <tr><td>&nbsp;</td><td>&nbsp;</td><td>&nbsp;</td><td>&nbsp;</td><td>&nbsp;</td><td>&nbsp;</td></tr>
    <tr><td>&nbsp;</td><td>&nbsp;</td><td>&nbsp;</td><td>&nbsp;</td><td>&nbsp;</td><td>&nbsp;</td></tr>
    <tr><td>&nbsp;</td><td>&nbsp;</td><td>&nbsp;</td><td>&nbsp;</td><td>&nbsp;</td><td>&nbsp;</td></tr>
</table>

Like the above,the target row should be the third row from the top.

BTW,I'm not fimiliar with jQuery, $().eq(0) selects the first one,

how to exclude the first one?

Will $().ne(0) work?

Answer 1

This should do it:

function not_just_nbsp() {
    return $(this).html() !== "#nbsp;";
}

$("#experiences td").filter(not_just_nbsp).filter(":first").parent();

Just replace the # in nbsp with an ampersand &. Had to do it like that to make it display here on StackOverflow.

Answer 2

To select all rows greater than the first row, you can do:

$('#experiences td:gt(0)')