Hey, I was wondering if anybody knew how to alter the following XSL stylesheet so that ANY text in my transformed XML will retain the carriage returns and line feeds (which will be \r\n as I feed it to the XML). I know I'm supposed to be using in some way but I can't seem to figure out how to get it working
<xsl:stylesheet xmlns:xsl=\"http://www.w3.org/1999/XSL/Transform\" version=\"1.0\">
<xsl:template match=\"/\"><xsl:apply-templates /></xsl:template><xsl:template match=\"\r\n\"><xsl:text> </xsl:text></xsl:template><xsl:template match=\"*\">
<xsl:element name=\"{local-name()}\"><xsl:value-of select=\"text()\"/><xsl:apply-templates select=\"*\"/></xsl:element ></xsl:template></xsl:stylesheet>