to the SSRS report server process that uses it? the name looks like a guid, but i need to find the reporting services reports that use it. thanks very much
A:
There doesn't appear to be a straightforward method to find this out.
The following query lists the subscription IDs and the reports to which they link
select s.SubscriptionID, c.Path
from ReportServer.dbo.Subscriptions as s
JOIN ReportServer.dbo.Catalog as c
on ItemID = Report_OID
The subscription ID is then referenced inside the job step, in the following format.
exec ReportServer.dbo.AddEvent @EventType='TimedSubscription', @EventData='~subscriptionID~'
It should be possible to write a query to join it all together, but I don't have time right now. I will try and update the question later.
Ed Harper
2009-09-01 15:04:07
thanks very muchdrew
dg
2009-09-22 02:34:18
+1
A:
Here's a query I blogged about a while back that does the join:
;WITH cte (job_id, job_name, execution_time, execution_order)
AS
(
SELECT DISTINCT j.job_id
,j.name
,CONVERT(datetime, STUFF(STUFF(run_date,7,0,'/'),5,0,'/')
+ SPACE(1)
+ STUFF(STUFF(RIGHT('000000' + CONVERT(varchar(20), run_time), 6),5,0,':'),3,0,':'))
,ROW_NUMBER() OVER (PARTITION BY j.job_id ORDER BY CONVERT(datetime, STUFF(STUFF(run_date,7,0,'/'),5,0,'/')
+ SPACE(1)
+ STUFF(STUFF(RIGHT('000000' + CONVERT(varchar(20), run_time), 6),5,0,':'),3,0,':')) DESC)
FROM msdb.dbo.sysjobs j
INNER JOIN msdb.dbo.syscategories c ON j.category_id = c.category_id
LEFT OUTER JOIN msdb.dbo.sysjobhistory jh ON j.job_id = jh.job_id
WHERE c.name ='Report Server'
)
SELECT
x.job_name
,c.name
,x.execution_time
,c.path
,su.description
,CONVERT(varchar(max), su.ExtensionSettings) as ExtensionSettings
,'EXEC msdb..sp_start_job ''' + x.job_name + '''' as SQLStatement
FROM cte x
INNER JOIN dbo.Schedule sc ON x.job_name = CONVERT(varchar(100), sc.ScheduleID)
INNER JOIN dbo.ReportSchedule rs ON sc.ScheduleID = rs.ScheduleID
INNER JOIN dbo.Subscriptions su ON rs.SubscriptionID = su.SubscriptionID
INNER JOIN dbo.Catalog c ON su.Report_OID = c.ItemID
WHERE execution_order = 1
ORDER BY 3, 2
StrateSQL
2009-09-01 23:30:40
fabulous...thank you very much, solved a really hard-to-figure-out problem for us.drew
dg
2009-09-22 02:35:57