tags:

views:

129

answers:

1
Q: 

SQL: return percentage without decimal place

Quick question; is there a way to apply numeric type on select statement?

exmaple usage

select (t1.f_count / (select count(*) from utb where user_id = 1))*100 as ratio

i need this to returns 60 instead of 60.0000

A: 

try

select ROUND((t1.f_count / (select count(*) from utb where user_id = 1))*100) as ratio
Pomyk  2009-09-08 18:51:51
missing a '(' after ROUND
Joshua  2009-09-08 18:57:31
indeed, fixed now :)
Pomyk  2009-09-08 19:05:01
thank you so much
ryan  2009-09-08 19:16:58

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