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xsl : getting specific node values from a table

Answer 1

A:

You could create a selector variable that holds the numeric position of columns you want. See the variable named "selector" below. Once you have that, a simple if in your TableData and TableColumn templates does the rest.

<?xml version="1.0" encoding="utf-8"?>
 <xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:DBE="foo.bar">

<xsl:variable name="selector">;1;5;7;12;</xsl:variable>

<xsl:template match="/">
    <xsl:apply-templates/>
</xsl:template>

<xsl:template match="DBE:Attribute">
    <html>
     <body><xsl:apply-templates/></body>
    </html>
</xsl:template>

<xsl:template match="DBE:Table">
    <table border="1">
     <xsl:apply-templates/>
    </table>
</xsl:template>

<xsl:template match="DBE:TableHeader">
  <tr>
    <xsl:apply-templates select="DBE:TableColumn"/>
    </tr>
</xsl:template>

<xsl:template match="DBE:TableColumn">  
  <xsl:variable name="pos">
    <xsl:text>;</xsl:text><xsl:value-of select="string(position())"/><xsl:text>;</xsl:text>
  </xsl:variable>

  <xsl:if test="contains($selector, $pos)">
  <th>
    <xsl:value-of select="."/>
  </th>
  </xsl:if>
</xsl:template>

<xsl:template match="DBE:TableRow">
  <tr>
    <xsl:apply-templates select="DBE:TableData"/>
  </tr>
</xsl:template>

<xsl:template match="DBE:TableData">
  <xsl:variable name="pos">
    <xsl:text>;</xsl:text><xsl:value-of select="string(position())"/><xsl:text>;</xsl:text>
  </xsl:variable>

  <xsl:if test="contains($selector, $pos)">
    <td>
      <xsl:value-of select="."/>
    </td>
  </xsl:if>
</xsl:template>

</xsl:stylesheet>

Andrew Cowenhoven 2009-09-16 16:16:14

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xsl : getting specific node values from a table

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