Good way to convert between short and bytes?

Question

I need to take pairs of bytes in, and output shorts, and take shorts in and output pairs of bytes. Here are the functions i've devised for such a purpose:

static short ToShort(short byte1, short byte2)
{
    short number = (short)byte2;
    number <<= 4;
    number += (short)byte1;
    return number;
}
static void FromShort(short number, out byte byte1, out byte byte2)
{
    byte byte2 = (byte)(number >> 4);
    short tempByte = (short)byte2 << 4;
    byte byte1 = (byte)(number - tempByte);
}

I think this is correct but i'm not sure. If this isn't the right way to do it, what is? is there a way to do this already in the framework?

Answer 1

Bytes are 8 bits, not 4, so your shifting is off. You also declared local variables in the second function so you wouldn't end up writing the the out parameters like you intend. It's also clearer/better if you limit yourself to bitwise operations (&, |, and ~) where possible.

static short ToShort(byte byte1, byte byte2)
{
    return (short) ((byte2 << 8) | (byte1 << 0));
}

static void FromShort(short number, out byte byte1, out byte byte2)
{
    byte2 = (byte) (number >> 8);
    byte1 = (byte) (number >> 0);
}

Note that the left and right shifts by zero are unnecessary, strictly speaking. I just put those in for symmetry. Also, personally I'd recommend you just learn bitwise arithmetic cold and skip writing helper functions like these. No need to hide the details with something so fundamental, IMHO.

Answer 2

Shorter version (also shifting 8 bits instead of 4):

static short ToShort(short byte1, short byte2)
{
    return (byte2 << 8) + byte1;
}

static void FromShort(short number, out byte byte1, out byte byte2)
{
    byte2 = (byte)(number >> 8);
    byte1 = (byte)(number & 255);
}

Answer 3

If you want to take bytes... take bytes; and your shifts are off, and | would be more intuitive:

static short ToShort(byte byte1, byte byte2)
{   // using Int32 because that is what all the operations return anyway...
    return (short)((((int)byte1) << 8) | (int)byte2);
}
static void FromShort(short number, out byte byte1, out byte byte2)
{
    byte1 = (byte)(number >> 8); // to treat as same byte 1 from above
    byte2 = (byte)number;
}

Answer 4

System.BitConverter

Answer 5

Use BitConverter

short number = 42;
byte[] numberBytes = BitConverter.GetBytes(number);
short converted = BitConverter.ToInt16(numberBytes);

Answer 6

gfgstatic short ToShort(short byte1, short byte2)