Is there any way to round up decimal value to its nearest 0.05 value in .Net?
Ex:
7.125 -> 7.15
6.66 -> 6.7
If its now available can anyone provide me the algo?
Excellent... Thanks
Prashant
2009-09-19 12:32:09
predator4: That seems to be what the OP wants, with the `6.66 -> 6.7` example.
caf
2009-09-19 13:36:49
@predator4: Its correct in my scenario (Tax calculation)
Prashant
2009-09-19 13:50:44
Sorry. Fair enough, I've missunderstood the round up thing. To reduce confusion I've deleted my comment.
2009-09-19 14:08:39
It should be noted that while this is a very good solution for the problem of rounding to arbitrary fractions, for decimal place rounding Math.Round should be used (just in case anyone comes looking at this question for a solution to more standard rounding).
ICR
2009-09-19 14:32:46
Just as a warning, this can go wrong if the input is within a factor of 20 of the max value of a decimal (so, greater than about 4*10^27 for the decimal type). You can get around this by subtracting Math.floor, rounding the non-integer part, and then adding it back to the floor value. But since the original questioner's use is for a tax calculation, I doubt it matters unless it has to work in Zimbabwe...
Steve Jessop
2009-09-19 14:33:53
+2
A:
Math..::.Round Method (Decimal, Int32, MidpointRounding)
Rounds a double-precision floating-point value to the specified number of fractional digits. A parameter specifies how to round the value if it is midway between two other numbers.
Math.Round(1.489,2,MidpointRounding.AwayFromZero)
Fredou
2010-02-08 05:53:17