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1

Hi all,

I have a Word document that I want to open and replace all instances of a social security number with the word, "test".

I already have the code to open the document. Here's the code that would do the replacement. However, I'm having trouble with using regular expressions at this point: _wordApp.Selection.Find.Text = ; within my code. Is using regular expressions a good approach or is there a better approach? Bear in mind, I have to match any social security number... hence: \b[0-9]{3}-[0-9]{2}-[0-9]{4}\b OR \b[0-9]{3}[0-9]{2}[0-9]{4}\b

Thanks in advance...

object replaceAll = Werd.WdReplace.wdReplaceAll;

_wordApp.Selection.Find.ClearFormatting();
_wordApp.Selection.Find.Text = ;

_wordApp.Selection.Find.Replacement.ClearFormatting();
_wordApp.Selection.Find.Replacement.Text = "test";

_wordApp.Selection.Find.Execute(ref nullobj, ref nullobj, ref nullobj, ref nullobj,
                ref nullobj, ref nullobj, ref nullobj, ref nullobj, ref nullobj, ref nullobj,
                ref replaceAll, ref nullobj, ref nullobj, ref nullobj, ref nullobj);
+2  A: 

MS Word has a wildcard matching capability built in. It's not as powerful as regular expressions, but it looks like it's able to match simple patterns like social security numbers.

(The < and > wildcards match start and end word boundaries.)

_wordApp.Selection.Find.ClearFormatting();
_wordApp.Selection.Find.MatchWildcards = true;
_wordApp.Selection.Find.Text = "<[0-9]{3}-[0-9]{2}-[0-9]{4}>"; // SSN with dashes.

_wordApp.Selection.Find.Replacement.ClearFormatting();
_wordApp.Selection.Find.Replacement.Text = "test";

_wordApp.Selection.Find.ClearFormatting();
_wordApp.Selection.Find.MatchWildcards = true;
_wordApp.Selection.Find.Text = "<[0-9]{9}>"; // SSN without dashes.

_wordApp.Selection.Find.Replacement.ClearFormatting();
_wordApp.Selection.Find.Replacement.Text = "test";
Chris R. Timmons
This answer was pretty close. I had to make some adjustments here and there, but I ended up with some working code... thanks much Chris..
Woody