I have a string "2009-10-08 08:22:02Z" which is iso8601 format. How do I use DateTime to parse this format ?
+3
A:
No, it's not ISO 8601. Valid ISO 8601 representation would have T
between time and date parts.
DateTime
can natively handle valid ISO 8601 formats. However, if you're stuck with this particular representation, you can try DateTime.ParseExact
and supply a fornat string.
Anton Gogolev
2009-10-08 09:21:02
Cheers but the wiki shows both formats
Kaya
2009-10-08 09:24:19
I was unable to parse my string using either "u" or "s" however replacing the T with a space is easily done. This seems to work. I'm using VB .NET with .NET 2.0.
sweeney
2010-09-23 16:51:13
+2
A:
string txt= "2009-10-08 08:22:02Z";
DateTime output = DateTime.ParseExact(txt, "u", System.Globalization.CultureInfo.InvariantCulture);
The DateTime class supports the standard format string of u for this format
I think for the ISO format (with the T separator), use "s" instead of "u". Or use:
string txt= "2009-10-08 08:22:02Z";
DateTime output = DateTime.ParseExact(txt, new string[] {"s", "u"}, System.Globalization.CultureInfo.InvariantCulture, System.Globalization.DateTimeStyles.None);
to support both formats.
JDunkerley
2009-10-08 09:22:24