visual c++: convert int into string pointer

Question

how to convert integer into string pointer in visual c++?

Answer 1

If you want a textual representation of the pointer address use sprintf. If you want to treat the numeric value as a pointer to a string use casting like so:

int intValue = ...;
char * charPtr = (char*)intValue;

Answer 2

You got homework? a generic one, tested if g++, http://effocore.googlecode.com/svn/trunk/devel/effo/codebase/addons/inl/include/impl/algo_impl.h :

#ifdef __cplusplus

static inline char *int2a_put(uintptr_t i, char *s)
{
    do {
     *s++ = '0' + i % 10;
     i /= 10;
    } while (i);

    return s;
}

static inline void int2a_reverse(char *head, char *tail)
{
    for (*tail = '\0'; --tail > head; ++head) {
     /* exchange */
     (*head) ^= (*tail);
     (*tail) ^= (*head);
     (*head) ^= (*tail);
    }
}

template<typename t>
static inline const char *int2a(t i, char *s)
{
    char *p;
    char *ret = s;
    bool f = false;

    p = s;
    if (i < 0) { 
     *p++ = '-';
     ++ s;
     /* 
      * In limits.h, INT_MAX was defined as 
      *   maximum values a `signed int' can hold.
      * and LONG_MAX was defined as maximum values 
      *   a `signed long int' can hold. 
      */
     switch (sizeof(t)) {
     case 8:
      {
       /* 
        * Inject \p a to prevent from complaint 
        *   of compiler.
        */
       ef64_t a = (ef64_t)i;
       if (-LLONG_MAX > a) {
        i = (t)LLONG_MAX;
        f = true;
       }
      }
      break;
     case 4:
     case 2:
     case 1:
      {
       /* 
        * Inject \p a to prevent from complaint 
        *   of compiler. 
        */
       int a = (int)i;
       if (-INT_MAX > a) {
        i = (t)INT_MAX;
        f = true;
       }
      }
      break;
     default:
      break;
     }
     if (!f) {
      i = -i;
     }
    }

    p = int2a_put((uintptr_t)i, p);

    if (f) {
     ++ *s;
    }

    int2a_reverse(s, p);

    return ret;
}

/*
 * No "static" otherwise g++ complains 
 *   "explicit template specialization cannot have a storage class"
 */
template<>
/*static*/ inline 
const char *int2a<uintptr_t>(uintptr_t i, char *s)
{
    char *p = int2a_put(i, s);

    int2a_reverse(s, p);

    return s;
}

#else

Answer 3

If you using CString, then you can use Format() method like this:

int val = 489;
CString s;
s.Format("%d", val);

Answer 4

search for atoi / itoa in your favorite documentation. Or try Boost (www.boost.org - library Conversion, lexical_cast).

Both ways are portable across different compilers.

Answer 5

Take any C and C++ textbook. This simple C code should work in Visual C++ and others C++ compilels and convert 489 into "489":

char result[100];
int num = 489;
sprintf(result, "%d", num);

Answer 6

Use stringstream

#include <sstream>
stringstream ss;
ss << i;
string   s = ss.str();

Answer 7

There is a very easy method

int i=4;
String ^ s = Convert::ToString(i);

Answer 8

basic C++

char text[100];
int num=123;
itoa(num,text,10);

Answer 9

This is how I did it in my homework since we were only allowed to use some predetermined libraries. I'm pretty sure it's not considered a "best practice" though ;)

string int2string(int integer) {
    string str;
    int division = integer;

    while (division > 0) {
     str = char('0' + (division % 10)) + str;
     division = division / 10;
    }

    return str;
}