I have a partitioned table like so:
create table demo (
ID NUMBER(22) not null,
TS TIMESTAMP not null,
KEY VARCHAR2(5) not null,
...lots more columns...
)
The partition is on the TS
column (one partition per year).
Since I search a lot via the timestamp, I created a combined index:
create index demo.x1 on demo (ts, key);
The query looks like this:
select *
from demo t
where t.TS = to_timestamp('2009-06-30 07:47:57', 'YYYY-MM-DD HH24:MI:SS')
I also tried to add and t.KEY = '00101'
but that doesn't help.
But EXPLAIN PLAN
says that TABLE ACCESS
and FULL
:
# Operation Options Object Mode Cost Bytes Cardinality
0 SELECT STATEMENT ALL_ROWS 583804 287145 2127
1 PARTITION RANGE ALL 583804 287145 2127
2 TABLE ACCESS FULL HEADER ANALYZED 583804 287145 2127
No mention of the index. What could be wrong?
[EDIT] For some reason, Oracle completely miscalculated the cost for the operation. I have 112 million rows in that table. The cost for a full scan of a single partition should be 20 million, not 600'000. That's why it even ignores optimizer hints.
[EDIT2] During my tests, I ran over this puzzling result. When I run this select
:
select tx_ts
from kt.header
where tx_ts = to_timestamp('2009-06-30 07:47:57', 'YYYY-MM-DD HH24:MI:SS')
I get this EXPLAIN PLAN:
0 SELECT STATEMENT ALL_ROWS 152 15616 1952
1 PARTITION RANGE ALL 152 15616 1952
2 INDEX FAST FULL SCAN HEADERX2 ANALYZED 152 15616 1952
So when I restrict myself to the indexed column as the result of the select
, Oracle decides to use the index. When I want to get all columns, I have to wait for a full table scan. What's going on here?
[EDIT2] Found it; see my answer below.