Calling method that uses method<Type>(paramaters)

Question

Given the example below, can someone please show me how this could be called?

bool WithinDelta<T>(T input1, T input2, T delta)

Ive tried various ways such as

bool foo = GenericMath.WithinDelta(1, 50, 75);
bool foo = GenericMath.WithinDelta<int>(1, 50, 75);

but the Type <T> is throwing me off.

Sorry for the basic question, but Im sick of beating my head on the desk over something this basic.

Answer 1

both ways are correct

Answer 2

Both of those should work fine. What's going wrong?

The first way is using type inference which works out the most appropriate type of T based on the arguments. It only works with generic methods rather than generic types, and there are various restrictions - although it's much more powerful in C# 3 than in C# 2.

Answer 3

As other people have pointed out both ways work and in this case are equivalent.

To give you another example which may help with the confusion, or potentially make it worse, you can also do the following

bool foo = GenericMath.WithinDelta<double>(1, 50, 75);

In this case the generic argument will force the type parameters of WithinDelta to be double values. So the compiler will then go through the process of ensuring the integer literals are converted to doubles before calling.