google maps, cellid to location

Question

According to this sample:

http://www.codeproject.com/KB/mobile/DeepCast.aspx

It's possible to request a gps coordinate (longitude & latitude) including range when sending cellid information (MCC, MNC, towerid, etc)

Can someone tell me the actual parameter to request/post to this address?

http://www.google.com/glm/mmap

It could be something like this

http://www.google.com/glm/mmap?mcc=xxx&mnc=xxx&towerid=xxx

And i would like to know what response we would get.

I have observe OpenCellid website and they provide some nice API to begin with, but i want to know about that in google map too (since they have more completed database).

OpenCellID API

Answer 1

As noted in other threads also check out https://labs.ericsson.com/apis/mobile-location/documentation/cell-id-look-up-api for a free cell-ID database to get coordinates from cellid, mcc, mnc, and lac .

Answer 2

You could use the Google Location API which is used by Firefox (Example see at http://www.mozilla.com/en-US/firefox/geolocation/ ) which has the url www.google.com/loc/json/. In fact this is JSON based webservice and a minimal Perl Example Look like this:

use LWP;

my $ua = LWP::UserAgent->new;
$ua->agent("TestApp/0.1 ");
$ua->env_proxy();

my $req = HTTP::Request->new(POST => 'https://www.google.com/loc/json');

$req->content_type('application/jsonrequest');
$req->content('{"cell_towers": [{"location_area_code": "8721", "mobile_network_code": "01", "cell_id": "7703", "mobile_country_code": "262"}], "version": "1.1.0", "request_address": "true"}');

# Pass request to the user agent and get a response back
my $res = $ua->request($req);

# Check the outcome of the response
if ($res->is_success) {
    print $res->content;
} else {
    print $res->status_line, "\n";
    return undef;
}

Please keep in mind that Google has not officially opened this API for other uses...

Answer 3

look at this url
http://www.anddev.org/poor_mans_gps_-_celltowerid_-_location_area_code_-lookup-t257.html

Answer 4

Here is example for work with

#!/usr/bin/python

country = 'fr'
#device = 'Sony_Ericsson-K750'
device = "Nokia N95 8Gb"
user_agent = 'Mozilla/4.0 (compatible; MSIE 5.5; Windows NT)'
mmap_url = 'http://www.google.com/glm/mmap'
geo_url = 'http://maps.google.com/maps/geo'

from struct import pack, unpack
from httplib import HTTP
import urllib2

def fetch_latlong_http(query):
    http = HTTP('www.google.com', 80)
    http.putrequest('POST', '/glm/mmap')
    http.putheader('Content-Type', 'application/binary')
    http.putheader('Content-Length', str(len(query)))
    http.endheaders()
    http.send(query)
    code, msg, headers = http.getreply()
    result = http.file.read()
    return result

def fetch_latlong_urllib(query):
    headers = { 'User-Agent' : user_agent }
    req = urllib2.Request(mmap_url, query, headers)
    resp = urllib2.urlopen(req)
    response = resp.read()
    return response

fetch_latlong = fetch_latlong_http

def get_location_by_cell(cid, lac, mnc=0, mcc=0, country='fr'):
    b_string = pack('>hqh2sh13sh5sh3sBiiihiiiiii',
                    21, 0,
                    len(country), country,
                    len(device), device,
                    len('1.3.1'), "1.3.1",
                    len('Web'), "Web",
                    27, 0, 0,
                    3, 0, cid, lac,
                    0, 0, 0, 0)

    bytes = fetch_latlong(b_string)
    (a, b,errorCode, latitude, longitude, c, d, e) = unpack(">hBiiiiih",bytes)
    latitude = latitude / 1000000.0
    longitude = longitude / 1000000.0

    return latitude, longitude

def get_location_by_geo(latitude, longitude):
    url = '%s?q=%s,%s&output=json&oe=utf8' % (geo_url, str(latitude), str(longitude))
    return urllib2.urlopen(url).read()

if __name__ == '__main__':
    print get_location_by_cell(20465, 495, 3, 262)
    print get_location_by_cell(20442, 6015)
    print get_location_by_cell(1085, 24040)
    print get_location_by_geo(40.714224, -73.961452)
    print get_location_by_geo(13.749113, 100.565327)

Answer 5

http://fiftyone.no-ip.org/files/geocodecelltower3.php?lac=16162&cid=55070378

Answer 6

how I can find location, with LAC and CELL ID .?