ansaurus

Question

Return multiple views to one ActionResult with ASP.NET MVC

Answer 1

+7 A:

Well, you can't return two values from a function, if that's what you are trying to do (the title suggests that's what you want).
Plus that's not how http works anyway. There's always just one response for a request.

But if you are trying to send both your viewOpenCalls and viewMyOpenCalls objects to one view, then you can do that with making your view have a model that'll hold both of them.

Like this :

//My VB is a bit rusty so I'm writing this in C#
class Calls {
    public yourDataType OpenCalls { get; set; }
    public yourDataType MyCalls { get; set; }
}

In your controller action :

return View(new Calls { OpenCalls = viewOpenCalls,  MyCalls = viewMyOpenCalls })

//I gues in VB it would be like this :
Dim viewOpenCalls = callRepository.FindAllOpenCalls()
Dim viewMyOpenCalls = callRepository.FindAllMyCalls(Session("LoggedInUser"))
Return View(New Calls _
    With {.OpenCalls = viewOpenCalls, .MyCalls = viewMyOpenCalls})

In your view make sure it's model is type of the Calls class.

<%@ Page Inherits="System.Web.Mvc.ViewPage<Calls>" %>

And now you can access the properties with <%=Model.OpenCalls %> and <%=Model.MyCalls %>

çağdaş 2009-10-21 10:05:39

What should I search for to find out how to do that?

Liam 2009-10-21 10:41:54

@Liam, I edited the answer.

çağdaş 2009-10-21 10:51:14

This is quite common, especially when returning multiple result sets from stored procedures. I do this in my MVC application - you just write containers for multiple sets of data to return to the view.

Kezzer 2009-10-21 10:56:28

Yes this is a good answer with clear example code.

Daniel Robinson 2009-10-21 11:03:48

Answer 2

+1 A:

1) Create a ViewData class. This is just a POCO class with properties defined for each data item you want to show on the view (e.g. OpenCallCount)

2) Create a strongly typed view that uses this ViewData class.

3) Pass a new instance of your ViewData class, with the properties set, to your view.

This will help you avoid using magic strings everywhere (e.g. ViewData("OpenCallCount") = ... becomes myViewDataClass.OpenCallCount = ...)

You could probably tidy up the view by using two partial view classes, or making it slightly more generic, but it will do the job at the moment.

Daniel Robinson 2009-10-21 10:52:55

Answer 3

A:

Once I'd worked out the correct way of doing it (a little while a go now) I got it working.

For reference, this is the way it should be done:

Public Class TheCalls
Private _OpenCalls As IQueryable(Of hdCall)
Public Property OpenCalls() As IQueryable(Of hdCall)
    Get
        Return _OpenCalls
    End Get
    Set(ByVal value As IQueryable(Of hdCall))
        _OpenCalls = value
    End Set
End Property
Private _AssignedCalls As IQueryable(Of hdCall)
Public Property AssignedCalls() As IQueryable(Of hdCall)
    Get
        Return _AssignedCalls
    End Get
    Set(ByVal value As IQueryable(Of hdCall))
        _AssignedCalls = value
    End Set
End Property
End Class

Liam 2009-12-08 15:29:38

ansaurus

tags:

views:

answers:

Return multiple views to one ActionResult with ASP.NET MVC

related questions