views:

93

answers:

2

How would I select all table elements that do not have any descendant td elements using jQuery 1.3.2?

+5  A: 

You could try:

$("table:not(:has(tbody > tr > td))").doStuff();

Working example:

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"&gt;
<html>
<head>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"&gt;&lt;/script&gt;
<script type="text/javascript">
$(function() {
  $("table:not(:has(tbody > tr > td))").css("background", "yellow");
});
</script>
<style type="text/css">
table { border-collapse: collapse; }
td, th { border: 1px solid black; }
</style>
</head>
<body>
<table>
<tr>
  <td>First table</td>
</tr>
</table>
<table>
<tr>
  <th>Second table</th>
</tr>
</table>
</body>
</html>
cletus
+1  A: 

You're looking for the CSS :not() selector.

table *:not(td)

Should do it.

Edit: bah, misread what you wanted.

Karl Guertin
On the right track, but `table`s generally will *never* have immediate children that are `td`s, so this won't work as written.
Sixten Otto
Yeah, ninja stealth edit. I think he's looking for the tables themselves rather than the tr/td/th I thought he was looking for.
Karl Guertin
Yup, I was looking for the tables themselves.
Emzo