weird for loop behaviour in firefox 3.5.3

Question

I maybe doing something wrong, but this seems quite weird to me:

for(i=1; i < 5; i++){ alert(i) }

in before mentioned firefox version gives me five counts of i. the question simply is: what the hell?

thanks!

SOLUTION: ok, it was my own mistake. i actually had an alert after the one in the loop which displayed number 5 :) thanks all who were ready to help and sorry for wasting your time.

Answer 1

What is the first value of i? What will be the last value of i, according to the loop conditional of i < 5?

Answer 2

I pasted javascript:for(i=1; i < 5; i++){ alert(i) } into my Firefox 3.5.3 address bar and it correctly alerted four times, 1-4.

Answer 3

It should only loop 4 times:

Granted yes, this is C++ code its the same concept:

#include <iostream>

using namespace std;

int main()
{
for (int i = 1; i < 5; i++)
{
cout << i << endl;
}
return 0;
}


$ ./test
1
2
3
4

I guess I am not understanding exactly what the question is.

Answer 4

Does your browser, in the page where you're seeing this problem, also give you five counts when you use a variable name other than "i"? Does it do it when you explicitly declare a local "i" like this:

for (var i = 1; i < 5; ++i) alert(i);

?