I came up with a solution that seems to work pretty well. It's a proof of concept, so you'll probably have to modify it a bit to work better for your specific case. Also, I only tested it in Firefox, but I don't see any reason why this wouldn't work in all the browsers. Anyway, here it is:
<script type="text/javascript">
$(document).ready(function() {
$('li').click(function() {
// the clicked LI
var clicked = $(this);
// all the LIs above the clicked one
var previousAll = clicked.prevAll();
// only proceed if it's not already on top (no previous siblings)
if(previousAll.length > 0) {
// top LI
var top = $(previousAll[previousAll.length - 1]);
// immediately previous LI
var previous = $(previousAll[0]);
// how far up do we need to move the clicked LI?
var moveUp = clicked.attr('offsetTop') - top.attr('offsetTop');
// how far down do we need to move the previous siblings?
var moveDown = (clicked.offset().top + clicked.outerHeight()) - (previous.offset().top + previous.outerHeight());
// let's move stuff
clicked.css('position', 'relative');
previousAll.css('position', 'relative');
clicked.animate({'top': -moveUp});
previousAll.animate({'top': moveDown}, {complete: function() {
// rearrange the DOM and restore positioning when we're done moving
clicked.parent().prepend(clicked);
clicked.css({'position': 'static', 'top': 0});
previousAll.css({'position': 'static', 'top': 0});
}});
}
});
});
</script>
<ul>
<li><a>Hank</a></li>
<li><a>Alice</a></li>
<li><a>Tom</a></li>
<li><a>Ashlee</a></li>
</ul>
It calculates the difference in offsets between the clicked LI
and first LI
and moves the clicked one up to the top by setting its position
to relative
and animating the top
property. Similarly, it calculates how much space was left behind by the clicked LI
and moves all the previous ones down accordingly. When it's done with the animations, it rearranges the DOM to match the new order and restores the positioning styles.
Hope that helps!