mprotect function called with 5 arguments

Question

Hello,

According to the Linux man page for mprotect the function has 3 Arguments:

int mprotect(const void *addr, size_t len, int prot);

but while running ltrace on a program that I'm analyzing I see that mprotect is called like this:

mprotect(0x8049000, 4096, 3, 1, 0xb7e057ac)      = 0

what are the 4th and 5th argument for??

Edit: Using ltrace version 0.5. and kernel 2.6.24-24-generic

thanks

Answer 1

Five is the number of arguments that ltrace will print if it can not find the description of the function in the config file. (/etc/ltrace.conf by default, I think).

On my system I can see the same behaviour, and the mprotect is not found there, only the SYS_mprotect.

If you want to have a second look of the ltrace source, the place of interest is the output.c, the conditional after "func = name2func(function_name);" - which prints 5 args in case the meta-info for the function name is not found (and in which case the linear lookup within the name2func returns NULL).

So, the manual is correct, it's ltrace which is "wrong" (quoted "wrong" because technically the code works as it should, though probably the defs in the config should be fixed)